14n^2-18n=6n

Solution for 14n^2-18n=6n equation:

14n^2-18n=6n

We move all terms to the left:

14n^2-18n-(6n)=0

We add all the numbers together, and all the variables

14n^2-24n=0

a = 14; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·14·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*14}=\frac{0}{28}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*14}=\frac{48}{28}
=1+5/7
$